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Old 05-15-2020, 20:29
GautamGreat GautamGreat is offline
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Quote:
Originally Posted by h4sh3m View Post
Hi

You can use this patterns :


It's not too hard bypassing this protector's registration (as I remember) but not tested on newer versions.


BR,
h4sh3m
Hi the last pattern seems working but if target is encrypted then the code section not decrypted and program crashes.

Can you give little more information about it? maybe some older notes you've wrote while analysis or anything
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