Armadillo ECDSA-113

[contextrax]

I did a more accurate calculation and I see now we have a 18% change of solving.
Here is the formula based on the wiki birthday page:
100*(1-exp(-((0xAD87E3B2BA1AE)**2)/(2*(2**112/(2*113)))))

Put this into google and it should print out ~18.36
0xAD87E3B2BA1AE is the current iteration of today

When we hit 2^52 iterations we have a ~35.69% chance of solving.
100*(1-exp(-((2**52)**2)/(2*(2**112/(2*113)))))

2^53 would give ~83% so I don't think we need to go this far

Need more CPU's